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CGP EDU Academic Team
Published on: August 14, 2026
Calculate the molality of KCl solution prepared by dissolving 7.45 g of KCl to make 500 mL of the solution. (d sol = 1.2 g mL –1 )
Text Solution
Verified by ExpertsThe correct answer is:
500
Molar mass of KCl = (39 + 35.5) g = 74.5 g
W 2 = 7.45 g, Mw 2 = 74.5 g
V sol = 500 mL
d sol = 1.2 g mL –1
m = 
In the above relation, W 1 is unknown, so find W 1 .
W 1 = (W sol – W 2 ) g = (V sol × d sol – W 2 ) g = (500 × 1.5 – 7.45) g
∴ m = 
= 0.168 mol kg –1 = 0.168 m.
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